0408-valid-word-abbreviation.py

# time complexity: O(n)
# space complexity: O(1)
class Solution:
    def validWordAbbreviation(self, word: str, abbr: str) -> bool:
        i = j = 0
        while j < len(abbr) and i < len(word):
            if abbr[j].isalpha():
                if abbr[j] != word[i]:
                    return False
                i += 1
                j += 1
            else:
                if abbr[j] == '0':
                    return False
                temp = 0
                while j < len(abbr) and abbr[j].isdigit():
                    temp = temp * 10 + int(abbr[j])
                    j += 1
                i += temp

        return j == len(abbr) and i == len(word)


word = "internationalization"
abbr = "i12iz4n"
print(Solution().validWordAbbreviation(word, abbr))
word = "apple"
abbr = "a2e"
print(Solution().validWordAbbreviation(word, abbr))
word = "abbde"
abbr = "a1b01e"
print(Solution().validWordAbbreviation(word, abbr))